CUET · MATHS · PYQ PAPER 2025
If \(I=\int \frac{x^4+x^2+1}{x^2-x+1} d x=a x+\beta x^2+\gamma x^3+\delta\), where \(\delta\) is the constant of integration, then \((a+2 \beta+3 \gamma)\) equals
- A \(0\)
- B 1
- C 2
- D 3
Answer & Solution
Correct Answer
(D) 3
Step-by-step Solution
Detailed explanation
\(I=\int \frac{(x^2-x+1)(x^2+x+1)}{x^2-x+1} d x\) \(I=\int (x^2+x+1) d x\) \(I=\frac{x^3}{3}+\frac{x^2}{2}+x+\delta\) Comparing with \(I=a x+\beta x^2+\gamma x^3+\delta\): \(a=1, \beta=\frac{1}{2}, \gamma=\frac{1}{3}\)…
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