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CUET · MATHS · PYQ PAPER 2025

If \(I=\int \frac{x^4+x^2+1}{x^2-x+1} d x=a x+\beta x^2+\gamma x^3+\delta\), where \(\delta\) is the constant of integration, then \((a+2 \beta+3 \gamma)\) equals

  1. A \(0\)
  2. B 1
  3. C 2
  4. D 3
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Answer & Solution

Correct Answer

(D) 3

Step-by-step Solution

Detailed explanation

\(I=\int \frac{(x^2-x+1)(x^2+x+1)}{x^2-x+1} d x\) \(I=\int (x^2+x+1) d x\) \(I=\frac{x^3}{3}+\frac{x^2}{2}+x+\delta\) Comparing with \(I=a x+\beta x^2+\gamma x^3+\delta\): \(a=1, \beta=\frac{1}{2}, \gamma=\frac{1}{3}\)…
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