CUET · MATHS · PYQ PAPER 2023
If \(f(x)=x+\frac{1}{x}\). Which of the following is not a correct option?
- A local minimum value \(=2\)
- B local maximum value \(=-2\), local minimum value \(=0\)
- C extremum occurs at \(1,-1\)
- D local maximum value \(=-2\)
Answer & Solution
Correct Answer
(B) local maximum value \(=-2\), local minimum value \(=0\)
Step-by-step Solution
Detailed explanation
\(f(x)=x+x^{-1}\) \(f'(x)=1-x^{-2}\) \(1-x^{-2}=0 \implies x^2=1 \implies x=\pm 1\) \(f''(x)=2x^{-3}\) \(f''(1)=2 > 0 \implies \text{local min at } x=1\) \(f(1)=1+\frac{1}{1}=2\) \(f''(-1)=-2 \(f(-1)=-1+\frac{1}{-1}=-2\) Local minimum value \(=2\) Local maximum value…
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