CUET · MATHS · PYQ PAPER 2023
If \(f(x)=\left\{\begin{array}{ll}\frac{\sin \pi x}{5 x}, & x \neq 0 \\ k, & x=0\end{array}\right.\) is continuous at \(x=0\), then \(k\) is :
- A \(\frac{5}{\pi}\)
- B \(\pi / 5\)
- C 1
- D \(0\)
Answer & Solution
Correct Answer
(B) \(\pi / 5\)
Step-by-step Solution
Detailed explanation
For continuity at \(x=0\), \( \lim_{x \to 0} f(x) = f(0) \). \( \lim_{x \to 0} \frac{\sin \pi x}{5 x} = \frac{\pi}{5} \lim_{x \to 0} \frac{\sin \pi x}{\pi x} \) \( = \frac{\pi}{5} \cdot 1 = \frac{\pi}{5} \) \( k = \frac{\pi}{5} \)
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