CUET · MATHS · PYQ PAPER 2023
If \(f(x)=\left\{\begin{array}{ll}\frac{\tan \left(\frac{\pi}{4}-x\right)}{\cot 2 x}, & x \neq \frac{\pi}{4} \\ k, & x=\frac{\pi}{4}\end{array}\right.\)
is continuous at \(x=\frac{\pi}{4}\), then the value of \(k\) is:
- A 1
- B 2
- C \(\frac{1}{2}\)
- D \(-\frac{1}{2}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
\(k = \lim_{x \to \frac{\pi}{4}} \frac{\tan \left(\frac{\pi}{4}-x\right)}{\cot 2 x}\) Applying L'Hôpital's Rule for \(\frac{0}{0}\) form: \(k = \lim_{x \to \frac{\pi}{4}} \frac{-\sec^2\left(\frac{\pi}{4}-x\right)}{-2\csc^2(2x)}\)…
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