CUET · MATHS · PYQ PAPER 2025
If \(f(x)=\left\{\begin{array}{ll}\frac{1-\tan x}{4 x-\pi} & x \neq \frac{\pi}{4} \\ k & x=\frac{\pi}{4}\end{array}\right.\) is continuous at \(x=\frac{\pi}{4}\), then the value of \(k\) is
- A 1
- B -1
- C \(\frac{1}{2}\)
- D \(\frac{-1}{2}\)
Answer & Solution
Correct Answer
(D) \(\frac{-1}{2}\)
Step-by-step Solution
Detailed explanation
\(k = \lim_{x \to \frac{\pi}{4}} \frac{1-\tan x}{4x-\pi}\) \(k = \lim_{x \to \frac{\pi}{4}} \frac{\frac{d}{dx}(1-\tan x)}{\frac{d}{dx}(4x-\pi)}\) (L'Hôpital's Rule) \(k = \lim_{x \to \frac{\pi}{4}} \frac{-\sec^2 x}{4}\) \(k = \frac{-\sec^2(\frac{\pi}{4})}{4}\)…
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