CUET · MATHS · PYQ PAPER 2023
If \(f(x)=3 x^2+10 x-5\), then by using the concept of differentials, the approximate value of \(f(2.03)\) is :
- A 37.66
- B 47.66
- C 17.66
- D 27.66
Answer & Solution
Correct Answer
(D) 27.66
Step-by-step Solution
Detailed explanation
\(f(2) = 3(2)^2 + 10(2) - 5 = 12 + 20 - 5 = 27\) \(f'(x) = 6x + 10\) \(f'(2) = 6(2) + 10 = 12 + 10 = 22\) \(f(2.03) \approx f(2) + f'(2)(0.03)\) \(f(2.03) \approx 27 + 22(0.03) = 27 + 0.66 = 27.66\)
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