CUET · MATHS · PYQ PAPER 2025
If \(e^x+e^y=e^{x+y}\), then \(\frac{d y}{d x}\) equals
- A \(-e^{y-x}\)
- B \(e^{y-x}\)
- C \(e^{x-y}\)
- D \(-e^{x-y}\)
Answer & Solution
Correct Answer
(A) \(-e^{y-x}\)
Step-by-step Solution
Detailed explanation
\(e^x + e^y \frac{dy}{dx} = e^{x+y}(1 + \frac{dy}{dx})\) \(e^x + e^y \frac{dy}{dx} = e^{x+y} + e^{x+y} \frac{dy}{dx}\) \(\frac{dy}{dx} (e^y - e^{x+y}) = e^{x+y} - e^x\) \(\frac{dy}{dx} = \frac{e^{x+y} - e^x}{e^y - e^{x+y}}\)…
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