CUET · MATHS · PYQ PAPER 2025
If \(\int \frac{d x}{(x-1)^{3 / 4}(x+2)^{5 / 4}}=\alpha[1-g(x)]^\beta+c\), where \(c\) is a constant of integration, then which of the
following are true?
(A) \(\alpha=\frac{2}{3}\)
(B) \(\beta=\frac{3}{4}\)
(C) \(3 \alpha+4 \beta=5\)
(D) \(g(x)=\frac{3}{x+2}\)
Choose the correct answer from the options given below:
- A (A), (B) and (D) only
- B (A), (B) and (C) only
- C (A), (B), (C) and (D)
- D (C) and (D) only
Answer & Solution
Correct Answer
(D) (C) and (D) only
Step-by-step Solution
Detailed explanation
\(\int \frac{d x}{(x-1)^{3 / 4}(x+2)^{5 / 4}} = \int \frac{d x}{\left(\frac{x-1}{x+2}\right)^{3 / 4}(x+2)^2}\) Let \(u = \frac{x-1}{x+2}\). \(du = \frac{(x+2)-(x-1)}{(x+2)^2} dx = \frac{3}{(x+2)^2} dx \implies \frac{1}{3} du = \frac{dx}{(x+2)^2}\).…
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