CUET · MATHS · PYQ PAPER 2025
If \(\left[\begin{array}{lll}1 & 2 & 1\end{array}\right]\left[\begin{array}{lll}1 & 2 & 0 \\ 2 & 0 & 1 \\ 1 & 0 & 2\end{array}\right]\left[\begin{array}{l}0 \\ 2 \\ x\end{array}\right]=0\), then value of x is
- A -1
- B 0
- C 1
- D 2
Answer & Solution
Correct Answer
(A) -1
Step-by-step Solution
Detailed explanation
\left[ \begin{array}{lll} 1 & 2 & 1 \end{array} \right] \left[ \begin{array}{lll} 1 & 2 & 0 \\ 2 & 0 & 1 \\ 1 & 0 & 2 \end{array} \right] = \left[ \begin{array}{lll} 1(1)+2(2)+1(1) & 1(2)+2(0)+1(0) & 1(0)+2(1)+1(2) \end{array} \right] = \left[ \begin{array}{lll} 6 & 2 & 4…
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