CUET · MATHS · PYQ PAPER 2025
If \(\left[\begin{array}{cc}2 x+1 & 5 x \\ 0 & y^2+1\end{array}\right]=\left[\begin{array}{cc}x+3 & 10 \\ 0 & 26\end{array}\right]\) , then the possible values of x + y are:
- A 2 and 5
- B 5 and -1
- C 7 and -3
- D 2 and -5
Answer & Solution
Correct Answer
(C) 7 and -3
Step-by-step Solution
Detailed explanation
\(2x+1 = x+3 \Rightarrow x = 2\) \(y^2+1 = 26 \Rightarrow y^2 = 25 \Rightarrow y = \pm 5\) \(x+y = 2+5 = 7\) \(x+y = 2+(-5) = -3\)
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