CUET · MATHS · PYQ PAPER 2023
If \(\left[\begin{array}{cc}2 x-1 & 4 x \\ 0 & y^2-1\end{array}\right]=\left[\begin{array}{cc}x+1 & 8 \\ 0 & 24\end{array}\right]\), then the value of \((x+y)\) is :
- A 7 and 2
- B 7 and 4
- C \(-4\) and \(3\)
- D 7 and -3
Answer & Solution
Correct Answer
(D) 7 and -3
Step-by-step Solution
Detailed explanation
\(2x-1 = x+1 \Rightarrow x = 2\) \(4x = 8 \Rightarrow 4(2) = 8\) \(y^2-1 = 24 \Rightarrow y^2 = 25 \Rightarrow y = \pm 5\) \(x+y = 2+5 = 7\) \(x+y = 2+(-5) = -3\)
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