CUET · MATHS · PYQ PAPER 2023
If \(\left[\begin{array}{cc}2 & -1 \\ 1 & 0 \\ -3 & 4\end{array}\right] A=\left[\begin{array}{ccc}-1 & -8 & -10 \\ 1 & -2 & -5 \\ 9 & 22 & 15\end{array}\right]\), then matrix \(A\) is equal to:
- A \(\left[\begin{array}{ccc}1 & 4 & -5 \\ 3 & -4 & 0\end{array}\right]\)
- B \(\left[\begin{array}{cc}1 & -2 \\ -5 & 3 \\ 4 & 0\end{array}\right]\)
- C \(\left[\begin{array}{ccc}1 & -2 & -5 \\ 3 & 4 & 0\end{array}\right]\)
- D \(\left[\begin{array}{cc}1 & -3 \\ 2 & -4 \\ 5 & 0\end{array}\right]\)
Answer & Solution
Correct Answer
(C) \(\left[\begin{array}{ccc}1 & -2 & -5 \\ 3 & 4 & 0\end{array}\right]\)
Step-by-step Solution
Detailed explanation
Let \(A=\left[\begin{array}{ccc}a & b & c \\ d & e & f\end{array}\right]\) From the second row of the product: \(\left[1 \cdot a+0 \cdot d \quad 1 \cdot b+0 \cdot e \quad 1 \cdot c+0 \cdot f\right]=\left[1 \quad -2 \quad -5\right]\) \(a=1, b=-2, c=-5\) From the first row of the…
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