CUET · MATHS · PYQ PAPER 2025
If \(A^T=\left[\begin{array}{cc}-2 & 3 \\ 1 & 2\end{array}\right]\) and \(B=\left[\begin{array}{cc}-1 & 0 \\ 1 & 2\end{array}\right]\), then the matrix \((A+2 B)^T\) is
- A \(\left[\begin{array}{cc}4 & 5 \\ -1 & -6\end{array}\right]\)
- B \(\left[\begin{array}{cc}-4 & -5 \\ 1 & 6\end{array}\right]\)
- C \(\left[\begin{array}{cc}-4 & 5 \\ 1 & 6\end{array}\right]\)
- D \(\left[\begin{array}{cc}4 & -5 \\ -1 & 6\end{array}\right]\)
Answer & Solution
Correct Answer
(C) \(\left[\begin{array}{cc}-4 & 5 \\ 1 & 6\end{array}\right]\)
Step-by-step Solution
Detailed explanation
\((A+2B)^T = A^T + (2B)^T = A^T + 2B^T\) \( = \left[\begin{array}{cc}-2 & 3 \\ 1 & 2\end{array}\right] + 2\left[\begin{array}{cc}-1 & 0 \\ 1 & 2\end{array}\right]^T\)…
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