CUET · MATHS · PYQ PAPER 2025
If a random variable \(x\) follows Polseon's distribution such that \(P(x=2)=9 P(x=4)+90 P(x=6)\), them sum of the mean and variance of \(x\) is
- A 4
- B 6
- C 1
- D 2
Answer & Solution
Correct Answer
(D) 2
Step-by-step Solution
Detailed explanation
\(\frac{e^{-\lambda} \lambda^2}{2!} = 9 \frac{e^{-\lambda} \lambda^4}{4!} + 90 \frac{e^{-\lambda} \lambda^6}{6!}\) \(\frac{\lambda^2}{2} = \frac{9 \lambda^4}{24} + \frac{90 \lambda^6}{720}\) \(\frac{\lambda^2}{2} = \frac{3 \lambda^4}{8} + \frac{\lambda^6}{8}\)…
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