CUET · MATHS · PYQ PAPER 2025
If A is an invertible matrix of order 3, then
| List-I | List-II |
| (A) \(|\operatorname{adj} A|\) | (I) \(8|A|\) |
| (B) \(|A(\operatorname{adj} A)|\) | (II) \(|A|^2\) |
| (C) \(|2 A|\) | (III) \(\frac{1}{|A|}\) |
| (D) \(\left|A^{-1}\right|\) | (IV) \(|A|^3\) |
- A (A) - (ii), (B) - (iv), (C) - (i), (D) - (iii)
- B (A) - (i), (B) - (ii), (C) - (iii), (D) - (iv)
- C (A) - (iii), (B) - (iv), (C) - (i), (D) - (ii)
- D (A) - (iv), (B) - (iii), (C) - (ii), (D) - (i)
Answer & Solution
Correct Answer
(A) (A) - (ii), (B) - (iv), (C) - (i), (D) - (iii)
Step-by-step Solution
Detailed explanation
(A) \(|\operatorname{adj} A| = |A|^{n-1} = |A|^{3-1} = |A|^2\) (B) \(|A(\operatorname{adj} A)| = ||A|I| = |A|^n|I| = |A|^3 \cdot 1 = |A|^3\) (C) \(|2 A| = 2^n|A| = 2^3|A| = 8|A|\) (D) \(\left|A^{-1}\right| = \frac{1}{|A|}\) (A) - (II), (B) - (IV), (C) - (I), (D) - (III)
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