CUET · MATHS · PYQ PAPER 2025
If \(A\) is an invertible matrix of order 3 and the determinant of \(A\) is 9, then the determinant of \(A^{-1}\) is :
- A 1
- B 9
- C 0
- D \(\frac{1}{9}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{9}\)
Step-by-step Solution
Detailed explanation
\(\det(A^{-1}) = \frac{1}{\det(A)}\) \(\det(A^{-1}) = \frac{1}{9}\)
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