CUET · MATHS · PYQ PAPER 2025
If \(A\) is a square matrix such that \(A^2=A\) and \(I\) is the identity matrix of the same order as \(A\), then \((I+2 A)^2-5 A\) is equal to :
- A \(I+2 A\)
- B \(I+3 A\)
- C \(I+A\)
- D \(I\)
Answer & Solution
Correct Answer
(B) \(I+3 A\)
Step-by-step Solution
Detailed explanation
\((I+2A)^2 = I^2 + 2AI + 2AI + (2A)^2\) \(= I + 4A + 4A^2\) Given \(A^2=A\): \(= I + 4A + 4A\) \(= I + 8A\) \((I+2A)^2 - 5A = (I+8A) - 5A\) \(= I+3A\)
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