CUET · MATHS · PYQ PAPER 2025
If A is a square matrix and I is an identity matrix of same order such that \(A^2=A\), then \((I+A)^3-8 I\) is equal to
- A A
- B \(A -I\)
- C \(7(A-I)\)
- D \(I\)
Answer & Solution
Correct Answer
(C) \(7(A-I)\)
Step-by-step Solution
Detailed explanation
\((I+A)^3 = I^3 + 3I^2A + 3IA^2 + A^3\) \(= I + 3A + 3A + A\) (since \(A^2=A \Rightarrow A^3=A\)) \(= I + 7A\) \((I+A)^3 - 8I = (I+7A) - 8I\) \(= 7A - 7I\) \(= 7(A-I)\)
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