CUET · MATHS · PYQ PAPER 2025
If \(\vec{a}, \vec{b}, \vec{c}\) are unit vectors such that \(\vec{a} \cdot \vec{b}=\vec{a} \cdot \vec{c}=0\), and the angle between \(\vec{b}\) and \(\vec{c}\) is \(\frac{\pi}{6}\), then
- A \(\vec{b}= \pm(\vec{a} \times \vec{c})\)
- B \(\vec{a}= \pm(\vec{b} \times \vec{c})\)
- C \(\vec{a}= \pm 2(\vec{b} \times \vec{c})\)
- D \(\vec{c}= \pm 2(\vec{a} \times \vec{b})\)
Answer & Solution
Correct Answer
(C) \(\vec{a}= \pm 2(\vec{b} \times \vec{c})\)
Step-by-step Solution
Detailed explanation
\(\vec{a} \cdot \vec{b}=0\) and \(\vec{a} \cdot \vec{c}=0 \implies \vec{a} \parallel (\vec{b} \times \vec{c})\) \(|\vec{b} \times \vec{c}| = |\vec{b}||\vec{c}|\sin(\frac{\pi}{6}) = (1)(1)(\frac{1}{2}) = \frac{1}{2}\) Since \(\vec{a}\) is a unit vector, \(|\vec{a}|=1\)…
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