CUET · MATHS · PYQ PAPER 2025
If \(\vec{a}, \vec{b}, \vec{c}\) are three mutually perpendicular unit vectors, then \(|\vec{a}+\vec{b}+\vec{c}|\) is equal to:
- A 3
- B 9
- C \(\sqrt{3}\)
- D 0
Answer & Solution
Correct Answer
(C) \(\sqrt{3}\)
Step-by-step Solution
Detailed explanation
\(|\vec{a}+\vec{b}+\vec{c}|^2 = |\vec{a}|^2+|\vec{b}|^2+|\vec{c}|^2 + 2(\vec{a}\cdot\vec{b} + \vec{b}\cdot\vec{c} + \vec{c}\cdot\vec{a})\) \(|\vec{a}+\vec{b}+\vec{c}|^2 = 1^2+1^2+1^2 + 2(0+0+0)\) \(|\vec{a}+\vec{b}+\vec{c}|^2 = 3\) \(|\vec{a}+\vec{b}+\vec{c}| = \sqrt{3}\)
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