CUET · MATHS · PYQ PAPER 2025
If \(\vec{a} \cdot \vec{b}=\vec{a} \cdot \vec{c}, \vec{a} \times \vec{b}=\vec{a} \times \vec{c}\) and \(\vec{a} \neq \overrightarrow{0}\), then the vector \(\vec{b}\) is equal to:
- A \(\overrightarrow{0}\)
- B \(\vec{c}\)
- C \(\vec{a}\)
- D \((\vec{a}+\vec{c})\)
Answer & Solution
Correct Answer
(B) \(\vec{c}\)
Step-by-step Solution
Detailed explanation
\(\vec{a} \cdot (\vec{b} - \vec{c}) = 0\) \(\vec{a} \times (\vec{b} - \vec{c}) = \overrightarrow{0}\) For \(\vec{a} \neq \overrightarrow{0}\), both conditions imply \((\vec{b} - \vec{c}) = \overrightarrow{0}\). \(\vec{b} = \vec{c}\)
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