CUET · MATHS · PYQ PAPER 2023
If \(A=\left[\begin{array}{lll}-1 & 2 & 3\end{array}\right], B=\left[\begin{array}{l}3 \\ 2 \\ 2\end{array}\right], C=\left[\begin{array}{lll}1 & 2 & 3\end{array}\right]\) and \(D=\left[\begin{array}{l}2 \\ 3 \\ 4\end{array}\right]\) then AB + CD is equal to :
- A [27]
- B [24]
- C 27
- D 28
Answer & Solution
Correct Answer
(A) [27]
Step-by-step Solution
Detailed explanation
\(AB = \left[-1 \cdot 3 + 2 \cdot 2 + 3 \cdot 2\right] = \left[-3 + 4 + 6\right] = \left[7\right]\) \(CD = \left[1 \cdot 2 + 2 \cdot 3 + 3 \cdot 4\right] = \left[2 + 6 + 12\right] = \left[20\right]\) \(AB + CD = \left[7\right] + \left[20\right] = \left[27\right]\)
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