CUET · MATHS · PYQ PAPER 2025
If \(A=\left[\begin{array}{ll}1 & 2 \\ 4 & 5\end{array}\right]\) then
Match List-I with List-II
| List-I | List-II |
| (A) \(\operatorname{det}(A)\) | (I) \(-\frac{1}{3}\) |
| (B) \(\operatorname{det}\left(A^{-1}\right)\) | (II) \(- 12\) |
| (C) \(\operatorname{det}(2 A)\) | (III) \(- 3\) |
| (D) \(\operatorname{det}\left( 3 A ^T\right)\) | (IV) \(- 27\) |
Choose the Correct answer from the options given below :
- A (A) - (I), (B) - (III), (C) - (II), (D) - (IV)
- B (A) - (III), (B) - (I), (C) - (II), (D) - (IV)
- C (A) - (III), (B) - (I), (C) - (IV), (D) - (II)
- D (A) - (I), (B) - (IV), (C) - (II), (D) - (III)
Answer & Solution
Correct Answer
(B) (A) - (III), (B) - (I), (C) - (II), (D) - (IV)
Step-by-step Solution
Detailed explanation
\(\operatorname{det}(A) = (1)(5) - (2)(4) = -3\) (A) \(\operatorname{det}(A) = -3 \implies\) (III) (B) \(\operatorname{det}\left(A^{-1}\right) = \frac{1}{\operatorname{det}(A)} = \frac{1}{-3} = -\frac{1}{3} \implies\) (I) (C)…
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