CUET · MATHS · PYQ PAPER 2025
If \(A=\left[\begin{array}{ll}1 & -1 \\ 2 & -1\end{array}\right], B=\left[\begin{array}{cc}a & 1 \\ b & -1\end{array}\right]\) and \((A+B)^2=A^2+B^2\) then
- A \(a=1, b=4\)
- B \(a=-1, b=4\)
- C \(a=2, b=-3\)
- D \(a=1, b=-4\)
Answer & Solution
Correct Answer
(A) \(a=1, b=4\)
Step-by-step Solution
Detailed explanation
\((A+B)^2=A^2+B^2 \Rightarrow A^2+AB+BA+B^2=A^2+B^2 \Rightarrow AB+BA=0\) \(AB = \left[\begin{array}{ll}1 & -1 \\ 2 & -1\end{array}\right] \left[\begin{array}{cc}a & 1 \\ b & -1\end{array}\right] = \left[\begin{array}{cc}a-b & 2 \\ 2a-b & 3\end{array}\right]\)…
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