CUET · MATHS · PYQ PAPER 2023
If \(A=\left[\begin{array}{ll}0 & 1 \\ 1 & 0\end{array}\right]\), then the value of \((A+I)^3-4 A\) is:
- A 8 A
- B \(4 I\)
- C \(8 A+4 I\)
- D \(3 A+I\)
Answer & Solution
Correct Answer
(B) \(4 I\)
Step-by-step Solution
Detailed explanation
\(A^2 = \left[\begin{array}{ll}0 & 1 \\ 1 & 0\end{array}\right] \left[\begin{array}{ll}0 & 1 \\ 1 & 0\end{array}\right] = \left[\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right] = I\) \((A+I)^3 = A^3 + 3A^2I + 3AI^2 + I^3\)…
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