CUET · MATHS · PYQ PAPER 2023
If \(A=\left[\begin{array}{cc}\alpha & \beta \\ \gamma & -\alpha\end{array}\right]\) is such that \(A^2=I\), then:
- A \(1+\alpha^2+\beta \gamma=0\)
- B \(1-\alpha^2+\beta \gamma=0\)
- C \(1-\alpha^2-\beta \gamma=0\)
- D \(1+\alpha^2-\beta \gamma=0\)
Answer & Solution
Correct Answer
(C) \(1-\alpha^2-\beta \gamma=0\)
Step-by-step Solution
Detailed explanation
A^2 = \left[\begin{array}{cc}\alpha & \beta \\ \gamma & -\alpha\end{array}\right]\left[\begin{array}{cc}\alpha & \beta \\ \gamma & -\alpha\end{array}\right] = \left[\begin{array}{cc}\alpha^2+\beta\gamma & \alpha\beta-\alpha\beta \\ \alpha\gamma-\alpha\gamma &…
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