CUET · MATHS · PYQ PAPER 2023
If \(A=\left[\begin{array}{cc}\cos \theta & \sin \theta \\ -\sin \theta & \cos \theta\end{array}\right]\), then \(A^2=\)
- A \(\left[\begin{array}{ll}\cos 2 \theta & -\sin 2 \theta \\ \sin 2 \theta & -\cos 2 \theta\end{array}\right]\)
- B \(\left[\begin{array}{cc}-\sin 2 \theta & \sin 2 \theta \\ \cos 2 \theta & \cos 2 \theta\end{array}\right]\)
- C \(\left[\begin{array}{cc}\cos 2 \theta & \sin 2 \theta \\ -\sin 2 \theta & \cos 2 \theta\end{array}\right]\)
- D \(\left[\begin{array}{ll}-\cos 2 \theta & \sin 2 \theta \\ -\sin 2 \theta & \cos 2 \theta\end{array}\right]\)
Answer & Solution
Correct Answer
(C) \(\left[\begin{array}{cc}\cos 2 \theta & \sin 2 \theta \\ -\sin 2 \theta & \cos 2 \theta\end{array}\right]\)
Step-by-step Solution
Detailed explanation
\(A^2 = \left[\begin{array}{cc}\cos \theta & \sin \theta \\ -\sin \theta & \cos \theta\end{array}\right] \left[\begin{array}{cc}\cos \theta & \sin \theta \\ -\sin \theta & \cos \theta\end{array}\right]\)…
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