CUET · MATHS · PYQ PAPER 2025
If \(A=\left[\begin{array}{cc}4 & 3 \\ 2 & -1 \\ 1 & 0\end{array}\right]\) and \(B^T=\left[\begin{array}{ccc}1 & 2 & 3 \\ 2 & 1 & -1\end{array}\right]\), then \(A-B\) is equal to
- A \(\left[\begin{array}{cc}1 & 2 \\ 2 & 1 \\ 3 & -1\end{array}\right]\)
- B \(\left[\begin{array}{cc}3 & 1 \\ -2 & 0 \\ -2 & 1\end{array}\right]\)
- C \(\left[\begin{array}{cc}3 & 1 \\ 0 & -2 \\ -2 & 1\end{array}\right]\)
- D \(\left[\begin{array}{cc}4 & 3 \\ 2 & -1 \\ 1 & 0\end{array}\right]\)
Answer & Solution
Correct Answer
(C) \(\left[\begin{array}{cc}3 & 1 \\ 0 & -2 \\ -2 & 1\end{array}\right]\)
Step-by-step Solution
Detailed explanation
\(B = \left[\begin{array}{cc}1 & 2 \\ 2 & 1 \\ 3 & -1\end{array}\right]\) \(A-B = \left[\begin{array}{cc}4-1 & 3-2 \\ 2-2 & -1-1 \\ 1-3 & 0-(-1)\end{array}\right] = \left[\begin{array}{cc}3 & 1 \\ 0 & -2 \\ -2 & 1\end{array}\right]\)
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