CUET · MATHS · PYQ PAPER 2025
If \(A=\left[\begin{array}{cc}3 & 1 \\ -1 & 2\end{array}\right]\) and \(I=\left[\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right]\), then the value of \(A^2-5 A+6 I\) is
- A \(\left[\begin{array}{cc}-1 & 0 \\ 0 & -1\end{array}\right]\)
- B \(\left[\begin{array}{ll}0 & 0 \\ 0 & 0\end{array}\right]\)
- C \(\left[\begin{array}{ll}1 & 1 \\ 1 & 1\end{array}\right]\)
- D \(\left[\begin{array}{cc}0 & -1 \\ -1 & 0\end{array}\right]\)
Answer & Solution
Correct Answer
(A) \(\left[\begin{array}{cc}-1 & 0 \\ 0 & -1\end{array}\right]\)
Step-by-step Solution
Detailed explanation
\(A^2 = \left[\begin{array}{cc}3 & 1 \\ -1 & 2\end{array}\right]\left[\begin{array}{cc}3 & 1 \\ -1 & 2\end{array}\right] = \left[\begin{array}{cc}9-1 & 3+2 \\ -3-2 & -1+4\end{array}\right] = \left[\begin{array}{cc}8 & 5 \\ -5 & 3\end{array}\right]\)…
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