CUET · MATHS · PYQ PAPER 2023
If \(A=\left[\begin{array}{cc}-2 & 3 \\ 1 & 2\end{array}\right]\) and \(B=\left[\begin{array}{cc}-1 & 0 \\ 2 & 3\end{array}\right]\), then \((3 A+2 B)^{\prime}\) is:
- A \(\left[\begin{array}{cc}-2 & 5 \\ 1 & 10\end{array}\right]\)
- B \(\left[\begin{array}{cc}8 & 13 \\ -2 & 12\end{array}\right]\)
- C \(\left[\begin{array}{cc}-8 & 7 \\ 9 & 12\end{array}\right]\)
- D \(\left[\begin{array}{cc}7 & 10 \\ -3 & 12\end{array}\right]\)
Answer & Solution
Correct Answer
(C) \(\left[\begin{array}{cc}-8 & 7 \\ 9 & 12\end{array}\right]\)
Step-by-step Solution
Detailed explanation
\(3A = 3\left[\begin{array}{cc}-2 & 3 \\ 1 & 2\end{array}\right] = \left[\begin{array}{cc}-6 & 9 \\ 3 & 6\end{array}\right]\) \(2B = 2\left[\begin{array}{cc}-1 & 0 \\ 2 & 3\end{array}\right] = \left[\begin{array}{cc}-2 & 0 \\ 4 & 6\end{array}\right]\)…
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