CUET · MATHS · PYQ PAPER 2023
If \(A=\left[\begin{array}{cc}1 & 0 \\ \frac{1}{3} & 1\end{array}\right]\) then \(A^{48}\) is :
- A \(\left[\begin{array}{cc}1 & 0 \\ 1 & 15\end{array}\right]\)
- B \(\left[\begin{array}{cc}1 & 0 \\ 16 & 1\end{array}\right]\)
- C \(\left[\begin{array}{cc}0 & 1 \\ 16 & 1\end{array}\right]\)
- D \(\left[\begin{array}{cc}1 & 0 \\ 15 & 1\end{array}\right]\)
Answer & Solution
Correct Answer
(B) \(\left[\begin{array}{cc}1 & 0 \\ 16 & 1\end{array}\right]\)
Step-by-step Solution
Detailed explanation
\(A^2 = \left[\begin{array}{cc}1 & 0 \\ \frac{1}{3} & 1\end{array}\right] \left[\begin{array}{cc}1 & 0 \\ \frac{1}{3} & 1\end{array}\right] = \left[\begin{array}{cc}1 & 0 \\ \frac{2}{3} & 1\end{array}\right]\)…
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