CUET · MATHS · PYQ PAPER 2025
If \(\vec{a}\) and \(\vec{b}\) are two vectors such that \(|\vec{a}|=10,|\vec{b}|=2\) and \(\vec{a} \cdot \vec{b}=12\), then \(|\vec{a} \times \vec{b}|\) is equal to
- A 16
- B 256
- C 20
- D 240
Answer & Solution
Correct Answer
(A) 16
Step-by-step Solution
Detailed explanation
\(|\vec{a} \times \vec{b}|^2 = (|\vec{a}| |\vec{b}|)^2 - (\vec{a} \cdot \vec{b})^2\) \(|\vec{a} \times \vec{b}|^2 = (10 \times 2)^2 - 12^2 = 20^2 - 12^2\) \(|\vec{a} \times \vec{b}|^2 = 400 - 144 = 256\) \(|\vec{a} \times \vec{b}| = \sqrt{256} = 16\)
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