CUET · MATHS · PYQ PAPER 2023
If A and B are two independent events then,
Match List I with List II
| List - I | List - II |
| (A) \(P(A \cup B)\) | (I) \(P\left(A^{\prime}\right) P\left(B^{\prime}\right)\) |
| (B) P(not A or not B) | (II) \(P(A) ; P(B) \neq 0\) |
| (C) \(P(A / B)\) | (III) \(1-P\left(A^{\prime}\right) P\left(B^{\prime}\right)\) |
| (D) P(neither A nor B) | (IV) \(1-P(A) P(B)\) |
- A A - I, B - IV, C - II, D - III
- B А - ІІ, В - III, C - I, D - IV
- C А - III, B - IV, C - II, D - I
- D A - IV, B - II, С - III, D - I
Answer & Solution
Correct Answer
(C) А - III, B - IV, C - II, D - I
Step-by-step Solution
Detailed explanation
\(P(A \cup B) = 1 - P((A \cup B)')\) \(= 1 - P(A' \cap B')\) \(= 1 - P(A')P(B')\) (A' and B' are independent) Thus, (A) matches (III). \(P(\text{not A or not B}) = P(A' \cup B')\) \(= P((A \cap B)')\) \(= 1 - P(A \cap B)\) \(= 1 - P(A)P(B)\) (A and B are independent) Thus, (B)…
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