CUET · MATHS · PYQ PAPER 2023
If \(a\) and \(b\) are the order and degree of the differential equation
\(\frac{\left[1+\left(\frac{d y}{d x}\right)^2\right]^{\frac{3}{2}}}{\frac{d^2 y}{d x^2}}=K \text { respectively, then }\)
the value of \(a+2 b\) is :
- A \(\frac{3}{2}\)
- B 2
- C 3
- D 6
Answer & Solution
Correct Answer
(D) 6
Step-by-step Solution
Detailed explanation
\(\left[1+\left(\frac{d y}{d x}\right)^2\right]^3=K^2 \left(\frac{d^2 y}{d x^2}\right)^2\) \(a = 2\) \(b = 2\) \(a+2b = 2+2(2) = 6\)
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