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CUET · MATHS · PYQ PAPER 2023

If A and B are square matrix of order \(n \times n\), then \((A-B)^2\) is equal to
A. \(A^2-A B-B A+B^2\)
B. \(A^2-2 A B+B^2\)
C. \(A^2-2 B A+B^2\)
D. \(\quad A^2-B^2\)
E. \(A^2+2 A B+B^2\)
Choose the correct answer from the options given below:

  1. A E only
  2. B C and E only
  3. C A only
  4. D A and C only
Verified Solution

Answer & Solution

Correct Answer

(C) A only

Step-by-step Solution

Detailed explanation

\((A-B)^2 = (A-B)(A-B)\) \(= A \cdot A - A \cdot B - B \cdot A + B \cdot B\) \(= A^2 - AB - BA + B^2\) The correct answer is A only.
From CUET
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