CUET · MATHS · PYQ PAPER 2023
If \(A\) and \(B\) are square matrices of the same order, then \((A+B)(A-B)\) is equal to
- A \(A^2-B^2\)
- B \(A^2-B A-A B-B^2\)
- C \(A^2-B A+B^2+A B\)
- D \(A^2-B^2+B A-A B\)
Answer & Solution
Correct Answer
(D) \(A^2-B^2+B A-A B\)
Step-by-step Solution
Detailed explanation
\(A(A-B)=A^2-A B\) \(B(A-B)=B A-B^2\) \((A+B)(A-B)=A^2-A B+B A-B^2\) \((A+B)(A-B)=A^2-B^2+B A-A B\)
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