CUET · MATHS · PYQ PAPER 2025
If A and B are invertible matrices of the same order, then \(( AB )^{-1}\) is equal to
- A \(A^{-1} B^{-1}\)
- B \(A^{-1} B\)
- C \(B^{-1} A^{-1}\)
- D \(A B^{-1}\)
Answer & Solution
Correct Answer
(C) \(B^{-1} A^{-1}\)
Step-by-step Solution
Detailed explanation
\(( AB )^{-1} = B^{-1} A^{-1}\)
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