CUET · MATHS · PYQ PAPER 2025
If \(A\) and \(B\) are independent events and \(P(A)=\frac{1}{2}, P(B)=\frac{1}{3}\) then
Match List-I with List-II
| List-I | List-II |
| (A) \(P(A \cap B)\) | (I) \(\frac{1}{2}\) |
| (B) \(P(\bar{A}) P(B)+P(A) P(\bar{B})\) | (II) \(\frac{1}{3}\) |
| (C) \(P(A \mid B)+P(B \mid A)\) | (III) \(\frac{1}{6}\) |
| (D) \(P(\overline{A \cap B})\) | (IV) \(\frac{5}{6}\) |
- A (A) (III), (B) - (I), (C) - (IV), (D) - (II)
- B (A) - (III), (B) - (IV), (C) - (I), (D) - (II)
- C (A) - (III), (B) - (IV), (C) - (II), (D) - (I)
- D (A) - (III), (B) – (II), (C) - (I), (D) - (IV)
Answer & Solution
Correct Answer
(A) (A) (III), (B) - (I), (C) - (IV), (D) - (II)
Step-by-step Solution
Detailed explanation
\(P(A)=\frac{1}{2}\) \(P(B)=\frac{1}{3}\) Since A and B are independent events: (A) \(P(A \cap B)\) \(P(A \cap B) = P(A)P(B)\) \(P(A \cap B) = \frac{1}{2} \cdot \frac{1}{3} = \frac{1}{6}\) (B) \(P(\bar{A}) P(B)+P(A) P(\bar{B})\)…
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