CUET · MATHS · PYQ PAPER 2025
If \(A(3,2), B(1,-1)\) and \(C(2,1)\) are three vertices of a parallelogram \(A B C D\), then its area (in sq. units) is equal to
- A 1
- B \(\frac{1}{2}\)
- C 5
- D \(\frac{5}{2}\)
Answer & Solution
Correct Answer
(A) 1
Step-by-step Solution
Detailed explanation
\(\vec{AB} = B - A = (1-3, -1-2) = (-2, -3)\) \(\vec{AD} = C - B = (2-1, 1-(-1)) = (1, 2)\) Area \( = |(-2)(2) - (-3)(1)|\) Area \( = |-4 + 3|\) Area \( = |-1|\) Area \( = 1\)
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