CUET · MATHS · PYQ PAPER 2025
If \(\vec{a}=2 \hat{j}-\hat{k}, \vec{b}=2 \hat{i}-3 \hat{j}+\hat{k}\) and \(\vec{c}=-\hat{i}+\hat{k}\) are three vectors, then the area (in sq, units) of the parallelogram whose diagonals are \((\vec{b}+\vec{c})\) and \((\vec{a}+\vec{c})\) is
- A \(\sqrt{21}\)
- B \(\frac{1}{2} \sqrt{21}\)
- C \(\sqrt{42}\)
- D 21
Answer & Solution
Correct Answer
(B) \(\frac{1}{2} \sqrt{21}\)
Step-by-step Solution
Detailed explanation
\( \vec{D_1} = \vec{b} + \vec{c} = (2\hat{i}-3\hat{j}+\hat{k}) + (-\hat{i}+\hat{k}) = \hat{i}-3\hat{j}+2\hat{k} \) \( \vec{D_2} = \vec{a} + \vec{c} = (2\hat{j}-\hat{k}) + (-\hat{i}+\hat{k}) = -\hat{i}+2\hat{j} \)…
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