CUET · MATHS · PYQ PAPER 2025
If 525 = (10 + K) (mod 7) where \(K \in N\), then the least value of K is:
- A 2
- B 4
- C 5
- D 6
Answer & Solution
Correct Answer
(B) 4
Step-by-step Solution
Detailed explanation
\(525 \equiv 0 \pmod{7}\) \(10 \equiv 3 \pmod{7}\) \(0 \equiv 3 + K \pmod{7}\) \(K \equiv -3 \pmod{7}\) \(K \equiv 4 \pmod{7}\) Least \(K = 4\)
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