CUET · MATHS · PYQ PAPER 2025
If \(\int \frac{2 x-5}{(2 x-3)^3} e^{2 x} d x=\frac{\lambda e^{2 x}}{(2 x-3)^2}+C\), where \(C\) is an arbitrary constant then the value of \(\lambda\) is :
- A \(\frac{1}{2}\)
- B \(2\)
- C \(-2\)
- D \(-\frac{1}{2}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
\( \frac{d}{dx} \left( \frac{\lambda e^{2 x}}{(2 x-3)^2} \right) = \lambda \left[ 2e^{2x}(2x-3)^{-2} + e^{2x}(-2)(2x-3)^{-3}(2) \right] \) \( = \lambda e^{2x} \left[ \frac{2}{(2x-3)^2} - \frac{4}{(2x-3)^3} \right] \)…
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