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CUET · MATHS · PYQ PAPER 2025

If \(\int \frac{2 x-5}{(2 x-3)^3} e^{2 x} d x=\frac{\lambda e^{2 x}}{(2 x-3)^2}+C\), where \(C\) is an arbitrary constant then the value of \(\lambda\) is :

  1. A \(\frac{1}{2}\)
  2. B \(2\)
  3. C \(-2\)
  4. D \(-\frac{1}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{1}{2}\)

Step-by-step Solution

Detailed explanation

\( \frac{d}{dx} \left( \frac{\lambda e^{2 x}}{(2 x-3)^2} \right) = \lambda \left[ 2e^{2x}(2x-3)^{-2} + e^{2x}(-2)(2x-3)^{-3}(2) \right] \) \( = \lambda e^{2x} \left[ \frac{2}{(2x-3)^2} - \frac{4}{(2x-3)^3} \right] \)…