CUET · MATHS · PYQ PAPER 2025
\(\text { If } \int \frac{1+x \log x}{x e^{-x}} d x=e^x f(x)+C \text {, }\)
where \(C\) is constant of integration, then \(f(x)\) is
- A \(e^x\)
- B \(\log x\)
- C \(\frac{1}{x}\)
- D \(\frac{1}{x^2}\)
Answer & Solution
Correct Answer
(B) \(\log x\)
Step-by-step Solution
Detailed explanation
\(\int \frac{1+x \log x}{x e^{-x}} d x = \int e^x \left( \frac{1}{x} + \log x \right) d x\) \(\text{Using } \int e^x (f(x) + f'(x)) dx = e^x f(x) + C\) \(f(x) = \log x\)
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