CUET · MATHS · PYQ PAPER 2023
If \(\sqrt{1-x^2}+\sqrt{1-y^2}=a(x-y)\),then \(\frac{d y}{d x}\) =
- A \(\sqrt{\frac{1-x^2}{1-y^2}}\)
- B \(\sqrt{\frac{1-y^2}{1-x^2}}\)
- C \(\sqrt{\frac{1-z^2}{1+y^2}}\)
- D \(\sqrt{\frac{1+x^2}{1-y^2}}\)
Answer & Solution
Correct Answer
(B) \(\sqrt{\frac{1-y^2}{1-x^2}}\)
Step-by-step Solution
Detailed explanation
Let \(x = \sin A\) and \(y = \sin B\). \(\cos A + \cos B = a(\sin A - \sin B)\) \(2\cos\left(\frac{A+B}{2}\right)\cos\left(\frac{A-B}{2}\right) = a \cdot 2\cos\left(\frac{A+B}{2}\right)\sin\left(\frac{A-B}{2}\right)\)…
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