CUET · MATHS · PYQ PAPER 2025
If \(\frac{1}{x^2}-\frac{1}{x}\) > 0, then \(x\) lies in the interval
- A \((-\infty, 0)\)
- B \((-\infty, 0) \cup(0,1)\)
- C \((-\infty, 1)\)
- D \((1, \infty)\)
Answer & Solution
Correct Answer
(B) \((-\infty, 0) \cup(0,1)\)
Step-by-step Solution
Detailed explanation
\(\frac{1-x}{x^2} > 0\) \(x^2 > 0 \implies x \neq 0\) \(1-x > 0 \implies x \(x \in (-\infty, 0) \cup (0, 1)\)
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