CUET · MATHS · PYQ PAPER 2023
If \(\Delta_1=\left|\begin{array}{lll}x & b & b \\ a & x & b \\ a & a & x\end{array}\right|\) and \(\Delta_2=\left|\begin{array}{ll}x & b \\ a & x\end{array}\right|\) are determinants, then :
- A \(\Delta_1=3\left(\Delta_2\right)^2\)
- B \(\frac{d}{d x}\left(\Delta_1\right)=3\left(\Delta_2\right)^2\)
- C \(\frac{d}{d x}\left(\Delta_1\right)=3 \Delta_2\)
- D \(\Delta_1=3\left(\Delta_2\right)^{\frac{3}{3}}\)
Answer & Solution
Correct Answer
(C) \(\frac{d}{d x}\left(\Delta_1\right)=3 \Delta_2\)
Step-by-step Solution
Detailed explanation
\(\Delta_2 = x \cdot x - b \cdot a = x^2 - ab\) \(\Delta_1 = x(x \cdot x - b \cdot a) - b(a \cdot x - b \cdot a) + b(a \cdot a - x \cdot a)\) \(\Delta_1 = x(x^2 - ab) - b(ax - ab) + b(a^2 - ax)\) \(\Delta_1 = x^3 - abx - abx + ab^2 + a^2b - abx = x^3 - 3abx + ab(a+b)\)…
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