CUET · MATHS · PYQ PAPER 2023
If \(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}=0\) then
\(\left|\begin{array}{ccc}1+a & 1 & 1 \\ 1 & 1+b & 1 \\ 1 & 1 & 1+c\end{array}\right|\) is equal to :
- A \(a b c\)
- B \(-a b c\)
- C \(0\)
- D 1
Answer & Solution
Correct Answer
(A) \(a b c\)
Step-by-step Solution
Detailed explanation
\(\left|\begin{array}{ccc}1+a & 1 & 1 \\ 1 & 1+b & 1 \\ 1 & 1 & 1+c\end{array}\right| \xrightarrow{R_1 \to R_1 - R_2, R_2 \to R_2 - R_3} \left|\begin{array}{ccc}a & -b & 0 \\ 0 & b & -c \\ 1 & 1 & 1+c\end{array}\right|\) \(= a(b(1+c) - (-c)(1)) - (-b)(0(1+c) - (-c)(1)) + 0\)…
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