CUET · MATHS · PYQ PAPER 2023
If \(\cos ^{-1} \sqrt{3} x+\cos ^{-1} x=\frac{\pi}{2}\), then the value of \(x\) is :
- A \(\frac{1}{2}\)
- B \(-\frac{1}{2}\)
- C \(\frac{1}{\sqrt{2}}\)
- D \(-\frac{1}{\sqrt{2}}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
\(\cos ^{-1} \sqrt{3} x = \frac{\pi}{2} - \cos ^{-1} x\) \(\cos ^{-1} \sqrt{3} x = \sin ^{-1} x\) \(\sqrt{3} x = \sqrt{1-x^2}\) \(3x^2 = 1-x^2\) \(4x^2 = 1\) \(x^2 = \frac{1}{4}\) \(x = \frac{1}{2}\) (since \(\sqrt{3}x \ge 0\))
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