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CUET · MATHS · PYQ PAPER 2025

If \(\int_0^1 \frac{e^x}{1+x} d x=m\), then the value of \(\int_0^1 \frac{e^x}{(1+x)^2} d x\) is :

  1. A \(m-e+1\)
  2. B \(\frac{m}{2}+e-1\)
  3. C \(m-\frac{e}{2}+1\)
  4. D \(m+\frac{e}{2}-1\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(m-\frac{e}{2}+1\)

Step-by-step Solution

Detailed explanation

\(m = \int_0^1 \frac{e^x}{1+x} d x\) Using integration by parts: \(\int u \, dv = uv - \int v \, du\), let \(u = \frac{1}{1+x}\) and \(dv = e^x \, dx\). \(du = -\frac{1}{(1+x)^2} dx\), \(v = e^x\)…
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