CUET · MATHS · PYQ PAPER 2025
If \(\int_0^1 \frac{e^x}{1+x} d x=m\), then the value of \(\int_0^1 \frac{e^x}{(1+x)^2} d x\) is :
- A \(m-e+1\)
- B \(\frac{m}{2}+e-1\)
- C \(m-\frac{e}{2}+1\)
- D \(m+\frac{e}{2}-1\)
Answer & Solution
Correct Answer
(C) \(m-\frac{e}{2}+1\)
Step-by-step Solution
Detailed explanation
\(m = \int_0^1 \frac{e^x}{1+x} d x\) Using integration by parts: \(\int u \, dv = uv - \int v \, du\), let \(u = \frac{1}{1+x}\) and \(dv = e^x \, dx\). \(du = -\frac{1}{(1+x)^2} dx\), \(v = e^x\)…
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