CUET · MATHS · PYQ PAPER 2025
How many minimum number of times must a man toss a fair coin so that the probability of having at least one head is more than \(90 \%\) ?
- A \(3\)
- B \(4\)
- C \(5\)
- D \(10\)
Answer & Solution
Correct Answer
(B) \(4\)
Step-by-step Solution
Detailed explanation
\(P(\text{at least one head}) = 1 - P(\text{all tails})\) \(1 - (0.5)^n > 0.9\) \((0.5)^n \(n = 4\)
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